Field Pocket Guide

Field Formulas

The relationships behind the calculators, each with a worked example. When you want the math itself, not the tool, it lives here.

01 Signals & scaling

Percent of span

% = (X − LRV) ÷ (URV − LRV) × 100

Where the value sits on the range. 75 on a 0–100 range is 75%.

mA from percent

mA = 4 + (% ÷ 100) × 16

50% of span is 12 mA. 0% = 4 mA, 100% = 20 mA. Scaling tool →

Percent from mA

% = (mA − 4) ÷ 16 × 100

12 mA reads 50%. A live 4 mA is 0%, not a dead loop.

Linear scaling

Out = OutLRV + (In − InLRV) ÷ (InURV − InLRV) × (OutURV − OutLRV)

Any span to any span. 50 °C on 0–100 °C maps to 12 mA on 4–20.

3–15 psi (pneumatic)

psi = 3 + (% ÷ 100) × 12

The old standard. 50% is 9 psi; 0% = 3 psi, 100% = 15 psi.

02 Flow & square root

Square-root extraction

%Flow = √(%DP)

Flow follows the root of differential pressure. 50% DP is 70.7% flow. Extraction tool →

Flow signal from DP signal

mA_flow = 4 + √((mA_DP − 4) ÷ 16) × 16

12 mA of linear DP becomes 15.31 mA of flow.

Flow vs differential pressure

Q ∝ √(ΔP)

Double the flow, quadruple the DP. Why a DP cell needs the root taken before it reads flow.

03 Calibration

Error, percent of span

Err% = (Measured − Ideal) ÷ (URV − LRV) × 100

Reads 12.1 mA where ideal is 12 on a 4–20 loop: +0.625% of span. Worksheet →

Turndown (rangeability)

TD = URV_max ÷ URV_min

A cell good from 10 to 250 inH2O has a 25:1 turndown.

Zero & span

Span = URV − LRV

Zero moves the LRV up or down; span sets how wide the range is. Adjust zero first, then span, then re-check zero.

04 Temperature

RTD, Pt100 (IEC 60751)

R = R0 (1 + A·t + B·t²),  t ≥ 0

A = 3.9083×10⁻³, B = −5.775×10⁻⁷, R0 = 100 Ω. At 100 °C, 138.51 Ω. RTD tool →

Thermocouple, cold junction

V_meter = E(hot) − E(reference)

The meter reads the difference. Type K hot 300 °C, terminals 25 °C ≈ 11.2 mV. TC tool →

Celsius & Fahrenheit

°F = °C × 9⁄5 + 32

100 °C = 212 °F. A 1 °C step is a 1.8 °F step.

05 Electrical

Ohm's law & power

V = I × R  ·  P = V × I

Across a 250 Ω HART resistor, 12 mA drops 3.0 V. Loop powered, two wires, one signal.

Loop burden

V_available ≥ 0.020 A × R_total

At full 20 mA, every 250 Ω needs 5 V of headroom. Add the wiring and the sense resistors before you trust the supply.

Examples are rounded for reading. The calculators carry full precision. Confirm against your facility's procedure and reference standard.

Still not reading right?

If the numbers here do not match what the loop is doing, the problem is usually the installation, the ranging, or the process itself rather than the device. Describe the symptom and a specialist answers by email, at no charge.